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assignment mismatch 1 variable but e.watch returns 2 values

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Home » Golang » Golang Find Output Programs

Golang Basics | Find Output Programs | Set 1

This section contains the Golang basics find output programs (set 1) with their output and explanations. Submitted by Nidhi , on August 06, 2021

Explanation:

In the above program, we used fmt.Print() , fmt.Println() , and fmt.Printf() functions to print the value of var1 variable.

There is no such printf() function in fmt package, the correct function is Printf() .

The above program will generate a syntax error because we created the variable var1 but it was not used.

While declaring the variable var1 , we used data type " Int " which is not defined in Golang. The correct data type for integer is " int ".

The above program will generate a syntax error, because the function fmt.Printf() returns two values but we used only one value as an lvalue.

Golang Find Output Programs »

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assignment mismatch 1 variable but e.watch returns 2 values

Golangで未使用の変数エラーを消す方法

stringconv.Atoi などのerrを二つ目の返り値として返してくれる関数を利用する際、errに代入した後使用しないと実行時にエラーが発生します。

しかしだからといって二つの返り値を変数に格納しないと、割り当てが間違っているという別のエラーが返却されることになります。

そのため必ず返り値を変数に代入する必要があるのですが、未使用エラーを発生させない必要があります。

このような状況の場合、 _ (アンダースコア)を利用するとエラーが発生しなくなります。

これはGo公式では Blank identifier という名称になっているようです。

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assignment mismatch: 2 variables but scanner.Text returns 1 value Go คือ วิธีแก้ไข

รันโค้ดภาษา Go (Golang) รับค่าจากผู้ใช้งานแต่พอรันแล้วไม่สำเร็จขึ้นข้อความ Error ว่า assignment mismatch: 2 variables but scanner.Text returns 1 value แบบนี้ต้องแก้ไขอย่างไร

ปัญหานี้เกิดจาก s, _ := เนื่องจากคำสั่ง scanner.Text จะส่งคืนค่า (return) แค่ค่าเดียว แต่ตอนประกาศตัวแปรมารับค่าประกาศ 2 ตัว คือ s กับ _ ซึ่งให้ลบในอักษร _ หรือ skip error ออก ดังนี้

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assignment mismatch: 2 variables but thrift.NewTSocketConf returns 1 value #52

@Lay523

Lay523 commented Oct 12, 2022

@citrusreticulata

citrusreticulata commented Oct 17, 2022

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citrusreticulata commented Feb 16, 2023

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