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## Eureka Math Grade 4 Module 3 Lesson 23 Answer Key

Engage ny eureka math 4th grade module 3 lesson 23 answer key, eureka math grade 4 module 3 lesson 23 problem set answer key.

Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 84? Answer: Yes, 2 is a factor of 84,

Explanation: 84 is a even number, 2 is a factor of every even number, ( 2 X 42 = 84).

b. Is 2 a factor of 83? Answer: No, 2 is not a factor of 83,

Explanation: 83 is a odd number, 2 is not a factor of odd numbers, So 2 is not a factor of 83, (2 X 41 = 82) and 82 + 1 = 83.

c. Is 3 a factor of 84? Answer: Yes, 3 is a factor of 84,

Explanation: 28 3| 84 -6 24 -24 0 So 3 is a factor of 84.

d. Is 2 a factor of 92? Answer: Yes, 2 is a factor of 92 and 92 is even number,

Explanation: 46 2| 92 – 8 12 -12 0 So 2 is a factor of 92.

e. Is 6 a factor of 84? Answer: Yes, 6 is a factor of 84 and 84 is even number,

Explanation: 14 6| 84 – 6 24 -24 0 So 6 is a factor of 84.

f. Is 4 a factor of 92? Answer: Yes, 4 is a factor of 92,

Explanation: 23 4| 92 – 8 12 -12 0 So 4 is a factor of 92.

g. Is 5 a factor of 84? Answer: No, 5 is not a factor of 84,

Explanation: 84 does not have 5 or 0 in ones place, all the numbers that have 5 as a factor have a 5 or 0 in ones place, So 5 is not a factor of 84.

h. Is 8 a factor of 92? Answer: No, 8 is not a factor of 92,

Explanation: 11 R4 8| 92 – 8 12 -08 04 So 8 is not a factor of 92 remainder is 4.

Question 2. Use the associative property to find more factors of 24 and 36. a. 24 = 12 × 2 = ( _4__ × 3) × 2 = __4_ × (3 × 2) = _4__ × 6 = __24_ Answer: 24 = 12 X 2 = (4 X 3) X 2 = 4 X (3 X 2) = 4 X 6 = 24,

Explanation: Used the associative property to find more factors of 24 as 24 = 12 X 2 = (4 X 3) X 2 = 4 X (3 X 2) = 4 X 6 = 24.

b. 36 = __9__ × 4 = ( __3__ × 3) × 4 = __3__ × (3 × 4) = __3__ × 12 = _36__ Answer: 36 = 9 X 4 = (3 X 3) X 4 = 3 X (3 X 4) = 3 X 12 = 36,

Explanation: Used the associative property to find more factors of 36 as 36 = 9 X 4 = (3 X 3) X 4 = 3 X (3 X 4) = 3 X 12 = 36.

Question 3. In class, we used the associative property to show that when 6 is a factor, then 2 and 3 are factors, because 6 = 2 × 3. Use the fact that 8 = 4 × 2 to show that 2 and 4 are factors of 56, 72, and 80. 56 = 8 × 7 72 = 8 × 9 80 = 8 × 10 Answer: 56 = 8 X 7 = (4 X 2) X 7 = 4 X (2 X 7) = 4 X 14 = 56,

72 = 8 X 9 = 8 X 9 = (4 X 2) X 9 = 4 X (2 X 9) = 4 X 18 = 72,

80 = 8 × 10 = 8 X 10 = (4 X 2) X 10 = 4 X (2 X 10) = 4 X 20 = 80,

Explanation: Used the fact that 8 = 4 × 2 to showed that 2 and 4 are factors of 56, 72, and 80 as

56 = 8 X 7 = (4 X 2) X 7 = 4 X (2 X 7) = 4 X 14 = 56,

80 = 8 × 10 = 8 X 10 = (4 X 2) X 10 = 4 X (2 X 10) = 4 X 20 = 80.

Question 4. The first statement is false. The second statement is true. Explain why, using words, pictures, or numbers. If a number has 2 and 4 as factors, then it has 8 as a factor. If a number has 8 as a factor, then both 2 and 4 are factors. Answer: 14 2|28 -2 08 -08 0 2 X 14 = 28, 7 4|28 -28 0 4 X 7 = 28, 3, R4 8|28 -24 04 28 has 2 and 4 as factors but not 8,

Explanation: The first statement is false. The second statement is true. If a number has 2 and 4 as factors, then it has 8 as a factor and If a number has 8 as a factor, then both 2 and 4 are factors, 14 2|28 -2 08 -08 0 2 X 14 = 28, 7 4|28 -28 0 4 X 7 = 28, 3, R4 8|28 -24 04 28 has 2 and 4 as factors but not 8, any number that can be divided exactly by 8 can also be divided by 2 and 4 instead, Since 8 = 2 X 4, Example: 8 X 5 = 40, (4 X 2) X 5 = 40.

## Eureka Math Grade 4 Module 3 Lesson 23 Exit Ticket Answer Key

Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 34? Answer: Yes, 2 is a factor of 34,

Explanation: 34 is a even number, 2 is a factor of every even number, (2 X 17 = 34), 17 R1 2| 34 – 2 14 -14 0 Yes, 2 is a factor of 34.

b. Is 3 a factor of 34? Answer: No, 3 is not a factor of 34,

Explanation: 11 R1 3| 34 – 3 04 -03 01 So 3 is not a factor of 34 remainder is 1.

c. Is 4 a factor of 72? Answer: Yes, 4 is a factor of 72,

Explanation: 18 4| 72 – 4 32 -32 0 So 4 is a factor of 72.

d. Is 3 a factor of 72? Answer: Yes, 3 is a factor of 72,

Explanation: 24 3| 72 – 6 12 -12 0 So 3 is a factor of 72.

Question 2. Use the associative property to explain why the following statement is true. Any number that has 9 as a factor also has 3 as a factor. Answer: Any number that has 9 as a factor also has 3 as a factor because 3 X 3 = 9,

Explanation: Let’s suppose 9 is a factor of the number N. That means N is 9 times some integer M. N = 9M, Since 9 = 3 × 3, we can also write N as N = 3 × 3 × M, That means N is 3 times some integer (3 × M). So 3 is also a factor of N.

## Eureka Math Grade 4 Module 3 Lesson 23 Homework Answer Key

Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 72? Answer: Yes, 2 is a factor of 72,

Explanation: 72 is a even number, 2 is a factor of every even number, (2 X 36 = 72), 36 2| 72 – 6 12 -12 0 Yes, 2 is a factor of 72.

b. Is 2 a factor of 73? Answer: No, 2 is not a factor of 73,

Explanation: 73 is a odd number, 2 is a factor of every even number not odd numbers, (2 X 36 = 72),72 + 1 = 73 36 R 1 2| 73 – 6 13 -12 1 No, 2 is not a factor of 73.

c. Is 3 a factor of 72? Answer: Yes, 2 is a factor of 72,

d. Is 2 a factor of 60? Answer: Yes, 2 is a factor of 60,

Explanation: 60 is a even number, 2 is a factor of every even number, (2 X 30 = 60), 30 2| 60 – 60 0 Yes, 2 is a factor of 60.

e. Is 6 a factor of 72? Answer: Yes, 6 is a factor of 72,

Explanation: (6 X 12 = 72), 12 6| 72 – 6 12 -12 0 Yes, 6 is a factor of 72.

f. Is 4 a factor of 60? Answer: Yes, 4 is a factor of 60,

Explanation: 60 is a even number, 4 is a factor of 60, (4 X 15 = 60), 15 4|60 -4 20 -20 0 Yes, 4 is a factor of 60.

g. Is 5 a factor of 72? Answer: No, 5 is not a factor of 72,

Explanation: 72 is a even number, 72 does not have 5 or 0 in ones place, all the numbers that have 5 as a factor have a 5 or 0 in ones place, So 5 is not a factor of 72. 14 R 2 5|72 -5 22 -20 2 No, 5 is not a factor of 72.

h. Is 8 a factor of 60? Answer: No, 8 is not a factor of 60,

Explanation: 60 is a even number, 8 is not a factor of 60, (8 X 7 = 56, remainder 4), 7 R 4 8|60 -56 04 No, 8 is not a factor of 60.

Question 2. Use the associative property to find more factors of 12 and 30. a. 12 = 6 × 2 = ( __3_ × 2) × 2 = _3__ × (2 × 2) = _3__ × _4__ = _12__ Answer: 12 = 6 X 2 = (3 X 2) X 2 = 3 X (2 X 2) = 3 X 4 = 12,

Explanation: Used the associative property to find more factors of 12 as 12 = 6 X 2 = (3 X 2) X 2 = 3 X (2 X 2) = 3 X 4 = 12.

b. 30 = __6__ × 5 = ( __2__ × 3) × 5 = __2__ × (3 × 5) = __2__ × 15 = __30__ Answer: 30 = 6 X 5 = (2 X 3) X 5 = 2 X (3 X 5) = 2 X 15 = 30,

Explanation: Used the associative property to find more factors of 30 as 30 = 6 X 5 = (2 X 3) X 5 = 2 X (3 X 5) = 2 X 15 = 30.

Question 3. In class, we used the associative property to show that when 6 is a factor, then 2 and 3 are factors, because 6 = 2 × 3. Use the fact that 10 = 5 × 2 to show that 2 and 5 are factors of 70, 80, and 90. 70 = 10 × 7 80 = 10 × 8 90 = 10 × 9 Answer: 70 = 10 X 7 = (5 X 2) X 7 = 5 X (2 X 7) = 5 X 14 = 70,

80 = 10 X 8 = 10 X 8 = (5 X 2) X 8 = 5 X (2 X 8) = 5 X 16 = 80,

90 = 10 × 9 = 10 X 9 = (5 X 2) X 9 = 5 X (2 X 9) = 5 X 18 = 90,

Explanation: Used the fact that 10 = 5 × 2 to showed that 2 and 5 are factors of 70, 80, and 90 as

70 = 10 X 7 = (5 X 2) X 7 = 5 X (2 X 7) = 5 X 14 = 70,

90 = 10 × 9 = 10 X 9 = (5 X 2) X 9 = 5 X (2 X 9) = 5 X 18 = 90.

Question 4. The first statement is false. The second statement is true. Explain why, using words, pictures, or numbers. If a number has 2 and 6 as factors, then it has 12 as a factor. If a number has 12 as a factor, then both 2 and 6 are factors. Answer: 9 2|18 -18 0 2 X 9 = 18, 3 6|18 -18 0 6 X 3 = 18, 1, R6 12|18 – 12 06 18 has 2 and 6 as factors but not 12,

Explanation: The first statement is false. The second statement is true. If a number has 2 and 6 as factors, then it has 12 as a factor and If a number has 12 as a factor, then both 2 and 6 are factors, 9 2|18 -18 0 2 X 9 = 18, 3 6|18 -18 0 6 X 3 = 18, 1, R6 12|18 – 12 06 18 has 2 and 6 as factors but not 12, any number that can be divided exactly by 12 can also be divided by 2 and 6 instead, Since 12 = 2 X 6.

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Engage NY Eureka Math 4th Grade Module 3 Lesson 24 Answer Key Eureka Math Grade 4 Module 3 Lesson 24 Problem Set Answer Key. Question 1. For each of the following, time yourself for 1 minute. See how many multiples you can write. a. Write the multiples of 5 starting from 100. Answer:

EngageNY/Eureka Math Grade 4 Module 3 Lesson 24For more Eureka Math (EngageNY) videos and other resources, please visit http://EMBARC.onlinePLEASE leave a me...

It's Homework Time! Help for fourth graders with Eureka Math Module 3 Lesson 24.

Grade 4 Module 3 Collapse all Expand all. Multi-Digit Multiplication and Division . Eureka Essentials: Grade 4 URL An outline of learning goals, key ideas, pacing suggestions, and more! Fluency Games URL. Teach Eureka Lesson ... Lesson 24 Video Page. Lesson PDF Page. Homework Solutions Page. Promethean ...

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Unit 1: Module 1: Place value, rounding, and algorithms for addition and subtraction. 0/2000 Mastery points. Topic A: Place value of multi-digit whole numbers Topic B: Comparing multi-digit whole numbers Topic C: Rounding multi-digit whole numbers. Topic D: Multi-digit whole number addition Topic E: Multi-digit whole number subtraction.

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Eureka Math ™ Grade 4, Module 3. Teacher Edition. ... GRADE. Mathematics Curriculum . 4 • MODULE 3. A STORY OF UNITS. This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org . ... Omit Lesson 33, and embed into Lesson 30 the discussion of the

As the creator of Engage NY Math and Eureka Math, Great Minds is the only place where you can get print editions of the PK-12 curriculum.Our printed materials are available in two configurations: Learn, Practice, Succeed, or student workbooks, teacher editions, assessment and fluency materials. The Learn, Practice, Succeed configuration is available for grades K-8 and offers teachers ...

EngageNY/Eureka Math Grade 4 Module 3 Lesson 3For more Eureka Math (EngageNY) videos and other resources, please visit http://EMBARC.onlinePLEASE leave a mes...

b. Draw a square around the multiples of 4. Look at the multiples of 4 that have an odd number in the tens place. What values do they have in the ones place? c. Look at the multiples of 4 that have an even number in the tens place. What values do they have in the ones place? Do you think this pattern would continue with multiples of 4 that are ...

EngageNY Math Grade 4 Module 3 Answer Key | Eureka Math 4th Grade Module 3 Answer Key. Eureka Math Grade 4 Module 3 Place Value, Rounding, and Algorithms for Addition and Subtraction. Eureka Math Grade 4 Module 3 Topic A Place Value of Multi-Digit Whole Numbers. Eureka Math Grade 4 Module 3 Lesson 1 Answer Key

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Lesson 4 Video Page. Lesson PDF Page. Homework Solutions Page. Promethean ... Grade 3 Module 3. Topic A:The Properties of Multiplication and Division. Lesson 1. Lesson 2. ... This work by EMBARC.Online based upon Eureka Math and is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

10 9 8 7 6 5 4 3 2 1 Eureka Math™ Grade 4, Module 4 Student File_A ... 1 Homework 4Lesson 3. a. Observe the familiar figures below. Label some points on each figure. ... This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org 4 G4-M4-SE-1.3.-05.2015. 42 Problem SetLesson 4 Name Date

Solve word problems using fraction and decimal multiplication, common core, tape diagrams, help students, help parents, help teachers

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It's Homework Time! Help for fourth graders with Eureka Math Module 5 Lesson 24.

So 3 is also a factor of N. Eureka Math Grade 4 Module 3 Lesson 23 Homework Answer Key. Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 72? Answer: Yes, 2 is a factor of 72, Explanation: 72 is a even number, 2 is a factor of every even number, (2 X 36 = 72), 36 2| 72 - 6 12 -12 0 Yes, 2 is a ...